Class 9 is a stepping stone to more advanced mathematics, and building strong fundamentals is key. The Maths Olympiad Sample Paper for Class 9 is designed to help students practise challenging problems, sharpen logical reasoning, and become familiar with the Olympiad exam format.
Download the free Class 9 Maths Olympiad Sample Paper in PDF format to help your child practise smartly, identify weak areas, and boost their confidence ahead of the exam.
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Section 1: Number Systems, Polynomials, Coordinate Geometry, Linear Equations in Two Variables, Introduction to Euclid’s Geometry, Lines and Angles, Triangles, Quadrilaterals, Areas of Parallelograms and Triangles, Circles, Constructions, Heron’s Formula, Surface Areas and Volumes, Statistics, Probability.
Achievers Section: Higher Order Thinking Questions - Syllabus as per Section 1
| Q.1 | Q.2 | Q.3 | Q.4 | Q.5 | Q.6 | Q.7 | Q.8 | Q.9 | Q.10 |
Q.1 |
A die is thrown once. Find the probability of getting a number less than 8. |
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Q.2 |
If (x + y + z) = 1, xy + yz + zx = -1, xyz = -1, then the value of x3 + y3 + z3 is: |
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Q.3 |
From four corners of a square sheet of side 4 cm, four pieces, each in the shape of an arc of a circle with a radius of 2 cm are cut out. The area of the remaining portion is: |
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Q.4 |
In the given figure, AP and BP are angle bisectors of ∠A and ∠B, respectively which meets at P on the parallelogram ABCD. Then 2∠APB = ? ![]() |
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Q.5 |
If (4 + 3√5)/(4 - 3√5) = a + b√5, then (a, b) = _______ |
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Q.6 |
ABCD is a rhombus with angle ABC = 56⁰, then angle ACD is equal to: ![]() |
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Q.7 |
The cost of a precious stone varies as the cube of its weight. The stone broke into 3 pieces whose weights are in the ratio 1:2:3. As a result, its cost is reduced. If the cost of the unbroken stone is $96,336, then find the loss incurred due to breakage. |
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Q.8 |
If x = a(b - c), y = b(c - a) and z = c(a - b), then (x/a)3 + (y/b)3 + (z/c)3 = ? |
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Q.9 |
In measuring the sides of a rectangle, there is an excess of 5% on one side and 2% deficit on the other. Then the error per cent in the area is: |
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Q.10 |
A right triangular prism of height 18 cm and of base sides 5 cm, 12 cm and 13 cm is transformed into another right triangular prism on a base of sides 9 cm, 12 cm and 15 cm. Find the height of the new prism and the change in the whole surface area: |
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Answers to Sample Questions from CREST Olympiads:
Q.1 : b | Q.2 : b | Q.3 : b | Q.4 : a | Q.5 : d | Q.6 : d | Q.7 : a | Q.8 : a | Q.9 : c | Q.10 : c