Worksheet on Mensuration

Worksheet of Mensuration for Grade 6

Solved Questions on Mensuration

1. Each rectangular tile is 50 centimetres long and 35 centimetres wide. How many tiles will be required to cover the floor of a room with a length of 9.45 metres and a breadth of 2.5 metres?

a) 115
b) 135
c) 155
d) 175

Answer: b) 135

Explanation: Length of the rectangular tile = 50 cm = 50/100 m = 0.5 m
Breadth of the rectangular tile = 35 cm = 35/100 m = 0.35 m
Area of the rectangular tile = Length × Breath = 0.5 m × 0.35 m 

Length of the floor of a room = 9.45 m
Breadth of the floor of a room = 2.5 m
Area of the floor of a room = Length × Breath = 9.45 m × 2.5 m 

Number of tiles = Area of the floor of a room/Area of the rectangular tile
= 9.45 m × 2.5 m/0.5 m × 0.35 m
= 945 m × 25 m × 10 × 100/100 × 5 m × 35 m × 10
= 135

2. Four regular hexagons of perimeter 300 cm each are joined. What is the perimeter of the new figure formed as shown in the given figure?

cmo-mensuration-c6-8

a) 300 cm
b) 600 cm
c) 900 cm
d) 1200 cm

Answer: c) 900 cm

Explanation: Perimeter of a regular hexagon = 300 cm
⇒ 6 × Side of a = 300 cm
⇒ Side = 300 cm/6
⇒ Side = 50 cm

The number of sides is marked in the figure.

cmo-mensuration-c6-9

There are 18 equal sides in the figure.

Perimeter of the new figure formed = Sum of the lengths of sides of the figure
= AB + BC + CD + DE + EF + FG + GH + HI + IJ + JK + KL + LM + MN + NO + OP + PQ + QR
= 18 × 50 cm
= 900 cm

3. The diameter of a circular field is 28 metres. How much distance will a man walk in order to make eight complete rounds of this field?

cmo-mensuration-c6-10

a) 604 m
b) 624 m
c) 704 m
d) 724 m

Answer: c) 704 m

Explanation: Diameter (d) of a circle field = 28 m
One Complete round  = Circumference of a circular field = πd
= 22/7 × 28
= 88 m

A man will walk in order to make eight complete rounds of this field
= 8 × One Complete round
= 8 × 88 m
= 704 m

4. What is the length of each side of the field if the cost of fencing a square plot at the rate of $2.50 per metre is $2700?

a) 270 m
b) 540 m
c) 720 m
d) 1080 m

Answer: a) 270 m

Explanation: Total cost of fencing a square plot = $2700
Rate of fencing per metre = $2.50

Perimeter of square = Total cost of fencing a square plot / Rate of fencing
= 2700/ 2.5
= 1080 m

Using the formula, perimeter of a square = 4 × Length of a side of a square plot
⇒  4 × Length of a side of a square plot = 1080 m
⇒ Length of a side of a square plot = 1080 m/4
⇒ Length of a side of a square plot = 270 m

5. What is the total estimated area of the given figure?

cmo-mensuration-c6-11

a) 5 sq. units
b) 5 sq. units
c) 5 sq. units
d) 5 sq. units

Answer: b) 17.5 sq. units

Explanation: Area of a square = 2.5 sq. units
Number of completely covered squares = 2
Estimation area due to completely covered squares = 2 × 2.5 sq. units
                                                                           = 5 sq. units

Number of  squares which is more than half covered squares = 2
Estimation area due to more than half covered squares = 2 × 2.5 sq. units
                                                                                 = 5 sq. units

Number of  squares which is exactly half covered square = ½ × 6 = 3
Estimation area due to exactly half covered square = 3 × 2.5 sq. units
                                                                           = 7.5 sq. units

Number of  squares which is less than half covered squares = 6

[Disregard any area that is less than half a square in size.]

Estimation area due to less than half covered squares = 0 sq. units

Total estimated area = 5 sq. units + 5 sq. units + 7.5 sq. units + 0 sq. units
                               = 17.5 sq. units

>> Join CREST Olympiads WhatsApp Channel for latest updates.

Maths Related Topics for Class 6

70%