Worksheet on Euclid's Geometry and Lines and Angles | Maths Grade 9

Worksheet on Euclid's Geometry and Lines and Angles

Solved Questions on Euclid’s Geometry and Lines and Angles

1. Which of the following axioms states that if a ray stands on a line, then the sum of the two adjacent angles so formed is 180° and the reverse is also true?

a) Adjacent angles axiom
b) Straight angles axiom
c) Linear pair axiom
d) Supplementary angles axiom

Answer: c) Linear pair axiom

Explanation: If a ray stands on a line, then the sum of the two adjacent angles so formed is 180° and the reverse is also true. This property is known as the linear pair axiom.

2. Which of the following is NOT true for Euclid's postulates?

Postulate I: It is possible to draw a circle with any centre and diameter.
Postulate II: A straight line can be drawn from any given point to another point.
Postulate III: Lines that coincide with each other are equal.
Postulate IV: There is only one line that goes through both of them if there are two different points.
Postulate V: A terminated line can be extended infinitely.

a) Only I and II
b) Only II and III
c) Only III and IV
d) Only IV and V

Answer: c) Only III and IV

Explanation: III and IV are Euclid's axioms, not postulates.

3. What is the value of angle z if AB || CD || EF and the angle y is one-third of angle x?

cmo-geometry-c9-25

a) 120°
b) 128°
c) 135°
d) 144°

Answer: c) 135°

Explanation: In the given figure, x and z are alternate angles (AB || EF) and y and z are co-interior angles (CD || EF).

cmo-geometry-c9-26

∠x = ∠z (alternate angles, AB || EF)

According to the question, ∠y = ? ∠x
⇒∠y = 13 ∠z 

∠y + ∠z = 180° (co-interior angles, CD || EF)
13 ∠z + ∠z = 180°
⇒ 4/3 ∠z = 180°
⇒ ∠z = 180° × 3/4
∴ ∠z = 135°

Hence, ∠x = ∠z = 135°

4. Which of the following is true if AB || DE?

cmo-geometry-c9-27

a) ∠ABC + ∠BCD + ∠CDE = 180º 
b) ∠ABC + ∠BCD − ∠CDE = 180º 
c) ∠ABC + ∠BCD + ∠CDE = 270º 
d) ∠ABC + ∠CDE − ∠BCD = 180º 

Answer: b) ∠ABC + ∠BCD − ∠CDE = 180°

Explanation: Draw a line CF through point C, making it parallel to both AB and DE.

Hence, AB || CF || DE. BC and CD are transversals.

The labelled diagram is shown as:

cmo-geometry-c9-28

∠1 + ∠2 = 180° (Co-interior angles, AB || CF) ……………….(i)
∠3 = ∠4 (Alternate angles, CF || DE) ………………….(ii)
Adding (i) and (ii), we get:
∠1 + ∠2 + ∠3 = 180° + ∠4
⇒ ∠1 + (∠2 + ∠3) = 180° +  ∠4  
⇒ ∠ABC + ∠BCD = 180° +  ∠CDE
∴ ∠ABC + ∠BCD − ∠CDE = 180º

5. What is the value of x, y and z if LI is parallel to ON, angle x is three-sevenths of the angle y and angle y is 1 ? times of angle z?

cmo-geometry-c9-29

a) ∠x = 36°; ∠y = 72°; ∠z = 45°
b) ∠x = 36°; ∠y = 72°; ∠z = 60°
c) ∠x = 36°; ∠y = 84°; ∠z = 45°
d) ∠x = 36°; ∠y = 84°; ∠z = 60°

Answer: d) ∠x = 36°; ∠y = 84°; ∠z = 60°

Explanation: Angle x is three-sevenths of the angle y.
⇒ ∠x = 3/7 × ∠y
Angle y is 1 25 times of angle z.
⇒ ∠y = 1 25 × ∠z
⇒ ∠y = 7/5 × ∠z
∴ ∠z = 5/7 × ∠y

∠x + ∠y + ∠z = 180° (Co-interior angles, LI || ON)
⇒ (3/7 × ∠y) + ∠y + (5/7 × ∠y) = 180°  [Put values of ∠x and ∠z in terms of ∠y]
⇒ (3/7 + 1 + 5/7) × ∠y = 180°                [Take ∠y as common]
⇒ (3 + 7 + 5)/7 × ∠y = 180°                   [Take LCM as 7]
⇒ 15/7 × ∠y = 180°
⇒ ∠y = 180° × 7/15
∴ ∠y = 84°

∠x = 3/7 × ∠y
⇒ ∠x = 3/7 × 84°
∴ ∠x = 36°

∠z = 5/7 × ∠y
⇒ ∠z = 5/7 × 84°
∴ ∠z = 60°

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